Learning center / Acoustics by building type / Bedroom and nursery

How many acoustic panels does a bedroom and nursery need?

A worked Sabine calculation for a typical bedroom, with panel counts for small, typical and large rooms.

2 minute read · Updated Nov 2026

The number of panels depends on three things: the room's volume, how much its surfaces already absorb, and how short you want the echo to be. Here is the calculation for a typical bedroom, step by step.

Step 1: the room

A typical bedroom of 13 × 12 ft with a 8 ft ceiling has a volume of about 1,248 ft³. With soft surfaces (carpet, upholstered furniture and curtains), its echo time is about 0.54 seconds. The target for bedrooms is 0.50 seconds.

Step 2: how much absorption is missing

Sabine's formula says RT60 = 0.161 × V ÷ A, with V in cubic meters and A, the total absorption, in square-meter sabins. To reach 0.50 s, the room needs about 122 ft² sabins of absorption in total. It already has about 114 from its surfaces, so the panels must add the rest.

Step 3: what one panel adds

A 24 × 48 in pill panel, 1 in thick has about 7.1 ft² of face. At NRC 0.80, and allowing for the surface it covers, it adds about 4.6 sabins.

Step 4: the answer

About 2 panels bring the room from 0.54 s to 0.50 s.

Same room, same panel size, different thickness.
ThicknessNRCPanels neededEcho time after
1 in0.820.50 s
2 in120.49 s
4 in1.1520.48 s
Panel counts scale with volume.
RoomSizeVolumeEcho time nowPanels needed
Small10 × 9 × 8 ft720 ft³0.46 s2
Typical13 × 12 × 8 ft1,248 ft³0.54 s2
Large20 × 18 × 10 ft3,600 ft³0.75 s26

These are estimates for speech frequencies (500–1,000 Hz). Use the room calculator with your own measurements, then load the result into the designer.