Learning center / Acoustics by building type / Conference room

How many acoustic panels does a conference room need?

A worked Sabine calculation for a typical conference room, with panel counts for small, typical and large rooms.

2 minute read · Updated Nov 2026

The number of panels depends on three things: the room's volume, how much its surfaces already absorb, and how short you want the echo to be. Here is the calculation for a typical conference room, step by step.

Step 1: the room

A typical conference room of 20 × 14 ft with a 9 ft ceiling has a volume of about 2,520 ft³. With hard and bare surfaces (tile, concrete, glass and little soft furniture), its echo time is about 2.11 seconds. The target for conference rooms is 0.50 seconds.

Step 2: how much absorption is missing

Sabine's formula says RT60 = 0.161 × V ÷ A, with V in cubic meters and A, the total absorption, in square-meter sabins. To reach 0.50 s, the room needs about 247 ft² sabins of absorption in total. It already has about 59 from its surfaces, so the panels must add the rest.

Step 3: what one panel adds

A 24 × 21 in hexagon panel, 2 in thick has about 2.6 ft² of face. At NRC 1.00, and allowing for the surface it covers, it adds about 2.5 sabins.

Step 4: the answer

About 77 panels bring the room from 2.11 s to 0.50 s.

Same room, same panel size, different thickness.
ThicknessNRCPanels neededEcho time after
1 in0.8970.50 s
2 in1770.50 s
4 in1.15670.49 s
Panel counts scale with volume.
RoomSizeVolumeEcho time nowPanels needed
Small15 × 11 × 9 ft1,485 ft³1.83 s43
Typical20 × 14 × 9 ft2,520 ft³2.11 s77
Large30 × 21 × 11 ft6,930 ft³2.86 s228

These are estimates for speech frequencies (500–1,000 Hz). Use the room calculator with your own measurements, then load the result into the designer.