Learning center / Acoustics by building type / House of worship

How many acoustic panels does a house of worship need?

A worked Sabine calculation for a typical sanctuary, with panel counts for small, typical and large rooms.

2 minute read · Updated Nov 2026

The number of panels depends on three things: the room's volume, how much its surfaces already absorb, and how short you want the echo to be. Here is the calculation for a typical sanctuary, step by step.

Step 1: the room

A typical sanctuary of 80 × 50 ft with a 24 ft ceiling has a volume of about 96,000 ft³. With typical surfaces (drywall, a rug and some furniture), its echo time is about 3.31 seconds. The target for sanctuaries is 1.40 seconds.

Step 2: how much absorption is missing

Sabine's formula says RT60 = 0.161 × V ÷ A, with V in cubic meters and A, the total absorption, in square-meter sabins. To reach 1.40 s, the room needs about 3,365 ft² sabins of absorption in total. It already has about 1,424 from its surfaces, so the panels must add the rest.

Step 3: what one panel adds

A 48 × 96 in rectangular panel, 2 in thick has about 32.0 ft² of face. At NRC 1.00, and allowing for the surface it covers, it adds about 28.8 sabins.

Step 4: the answer

About 68 panels bring the room from 3.31 s to 1.39 s.

Same room, same panel size, different thickness.
ThicknessNRCPanels neededEcho time after
1 in0.8871.40 s
2 in1681.39 s
4 in1.15581.40 s
Panel counts scale with volume.
RoomSizeVolumeEcho time nowPanels needed
Small60 × 38 × 24 ft54,720 ft³2.90 s35
Typical80 × 50 × 24 ft96,000 ft³3.31 s68
Large120 × 75 × 26 ft234,000 ft³4.08 s188

These are estimates for speech frequencies (500–1,000 Hz). Use the room calculator with your own measurements, then load the result into the designer.