Learning center / Acoustics by building type / Home office

How many acoustic panels does a home office need?

A worked Sabine calculation for a typical home office, with panel counts for small, typical and large rooms.

2 minute read · Updated Nov 2026

The number of panels depends on three things: the room's volume, how much its surfaces already absorb, and how short you want the echo to be. Here is the calculation for a typical home office, step by step.

Step 1: the room

A typical home office of 12 × 10 ft with a 8 ft ceiling has a volume of about 960 ft³. With typical surfaces (drywall, a rug and some furniture), its echo time is about 0.80 seconds. The target for home offices is 0.45 seconds.

Step 2: how much absorption is missing

Sabine's formula says RT60 = 0.161 × V ÷ A, with V in cubic meters and A, the total absorption, in square-meter sabins. To reach 0.45 s, the room needs about 105 ft² sabins of absorption in total. It already has about 59 from its surfaces, so the panels must add the rest.

Step 3: what one panel adds

A 24 × 48 in rectangular panel, 2 in thick has about 8.0 ft² of face. At NRC 1.00, and allowing for the surface it covers, it adds about 7.2 sabins.

Step 4: the answer

About 7 panels bring the room from 0.80 s to 0.43 s.

Same room, same panel size, different thickness.
ThicknessNRCPanels neededEcho time after
1 in0.890.43 s
2 in170.43 s
4 in1.1560.43 s
Panel counts scale with volume.
RoomSizeVolumeEcho time nowPanels needed
Small9 × 8 × 8 ft576 ft³0.68 s3
Typical12 × 10 × 8 ft960 ft³0.80 s7
Large18 × 15 × 10 ft2,700 ft³1.10 s25

These are estimates for speech frequencies (500–1,000 Hz). Use the room calculator with your own measurements, then load the result into the designer.